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SQL code copied to buffer
Task 152:

Clients with a high number of rentals

MySQL
Create an SQL query to find customers who have rented more movies than the average number of rentals among all customers. Use a subquery to calculate the average number of rentals.
The resulting table should contain the following columns: customer_id - unique customer identifier, first_name - customer name, last_name - client’s last name.
rental_count - number of films rented.
Expected result Columns: 4 · Rows: 296
customer_id first_name last_name rental_count

Sample rows open after wrong checks: 0 of 2

Write your query below and click "Check it!". Tables are described in the right pane.

Tutorial
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